6(4z+2)=3(8z+4)

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Solution for 6(4z+2)=3(8z+4) equation: 


Simplifying
6(4z + 2) = 3(8z + 4)

Reorder the terms:
6(2 + 4z) = 3(8z + 4)
(2 * 6 + 4z * 6) = 3(8z + 4)
(12 + 24z) = 3(8z + 4)

Reorder the terms:
12 + 24z = 3(4 + 8z)
12 + 24z = (4 * 3 + 8z * 3)
12 + 24z = (12 + 24z)

Add '-12' to each side of the equation.
12 + -12 + 24z = 12 + -12 + 24z

Combine like terms: 12 + -12 = 0
0 + 24z = 12 + -12 + 24z
24z = 12 + -12 + 24z

Combine like terms: 12 + -12 = 0
24z = 0 + 24z
24z = 24z

Add '-24z' to each side of the equation.
24z + -24z = 24z + -24z

Combine like terms: 24z + -24z = 0
0 = 24z + -24z

Combine like terms: 24z + -24z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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