6(4z-1)-2(z+8)=13(z+1)

Solution for 6(4z-1)-2(z+8)=13(z+1) equation:

6(4z-1)-2(z+8)=13(z+1)

We move all terms to the left:

6(4z-1)-2(z+8)-(13(z+1))=0

We multiply parentheses

24z-2z-(13(z+1))-6-16=0


We calculate terms in parentheses: -(13(z+1)), so:

13(z+1)

We multiply parentheses

13z+13

Back to the equation:

-(13z+13)


We add all the numbers together, and all the variables

22z-(13z+13)-22=0

We get rid of parentheses

22z-13z-13-22=0

We add all the numbers together, and all the variables

9z-35=0

We move all terms containing z to the left, all other terms to the right

9z=35

z=35/9

z=3+8/9