6(4z-1)-3(2+4)=10(z+1)

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Solution for 6(4z-1)-3(2+4)=10(z+1) equation:


Simplifying
6(4z + -1) + -3(2 + 4) = 10(z + 1)

Reorder the terms:
6(-1 + 4z) + -3(2 + 4) = 10(z + 1)
(-1 * 6 + 4z * 6) + -3(2 + 4) = 10(z + 1)
(-6 + 24z) + -3(2 + 4) = 10(z + 1)

Combine like terms: 2 + 4 = 6
-6 + 24z + -3(6) = 10(z + 1)

Multiply -3 * 6
-6 + 24z + -18 = 10(z + 1)

Reorder the terms:
-6 + -18 + 24z = 10(z + 1)

Combine like terms: -6 + -18 = -24
-24 + 24z = 10(z + 1)

Reorder the terms:
-24 + 24z = 10(1 + z)
-24 + 24z = (1 * 10 + z * 10)
-24 + 24z = (10 + 10z)

Solving
-24 + 24z = 10 + 10z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-10z' to each side of the equation.
-24 + 24z + -10z = 10 + 10z + -10z

Combine like terms: 24z + -10z = 14z
-24 + 14z = 10 + 10z + -10z

Combine like terms: 10z + -10z = 0
-24 + 14z = 10 + 0
-24 + 14z = 10

Add '24' to each side of the equation.
-24 + 24 + 14z = 10 + 24

Combine like terms: -24 + 24 = 0
0 + 14z = 10 + 24
14z = 10 + 24

Combine like terms: 10 + 24 = 34
14z = 34

Divide each side by '14'.
z = 2.428571429

Simplifying
z = 2.428571429

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