6(4z-1)-4(z+2)=15(z+1)

Solution for 6(4z-1)-4(z+2)=15(z+1) equation:

Simplifying
6(4z + -1) + -4(z + 2) = 15(z + 1)

Reorder the terms:
6(-1 + 4z) + -4(z + 2) = 15(z + 1)
(-1 * 6 + 4z * 6) + -4(z + 2) = 15(z + 1)
(-6 + 24z) + -4(z + 2) = 15(z + 1)

Reorder the terms:
-6 + 24z + -4(2 + z) = 15(z + 1)
-6 + 24z + (2 * -4 + z * -4) = 15(z + 1)
-6 + 24z + (-8 + -4z) = 15(z + 1)

Reorder the terms:
-6 + -8 + 24z + -4z = 15(z + 1)

Combine like terms: -6 + -8 = -14
-14 + 24z + -4z = 15(z + 1)

Combine like terms: 24z + -4z = 20z
-14 + 20z = 15(z + 1)

Reorder the terms:
-14 + 20z = 15(1 + z)
-14 + 20z = (1 * 15 + z * 15)
-14 + 20z = (15 + 15z)

Solving
-14 + 20z = 15 + 15z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-15z' to each side of the equation.
-14 + 20z + -15z = 15 + 15z + -15z

Combine like terms: 20z + -15z = 5z
-14 + 5z = 15 + 15z + -15z

Combine like terms: 15z + -15z = 0
-14 + 5z = 15 + 0
-14 + 5z = 15

Add '14' to each side of the equation.
-14 + 14 + 5z = 15 + 14

Combine like terms: -14 + 14 = 0
0 + 5z = 15 + 14
5z = 15 + 14

Combine like terms: 15 + 14 = 29
5z = 29

Divide each side by '5'.
z = 5.8

Simplifying
z = 5.8