6(4z-1)-5(z+1)=2(z+1)

Solution for 6(4z-1)-5(z+1)=2(z+1) equation:

Simplifying
6(4z + -1) + -5(z + 1) = 2(z + 1)

Reorder the terms:
6(-1 + 4z) + -5(z + 1) = 2(z + 1)
(-1 * 6 + 4z * 6) + -5(z + 1) = 2(z + 1)
(-6 + 24z) + -5(z + 1) = 2(z + 1)

Reorder the terms:
-6 + 24z + -5(1 + z) = 2(z + 1)
-6 + 24z + (1 * -5 + z * -5) = 2(z + 1)
-6 + 24z + (-5 + -5z) = 2(z + 1)

Reorder the terms:
-6 + -5 + 24z + -5z = 2(z + 1)

Combine like terms: -6 + -5 = -11
-11 + 24z + -5z = 2(z + 1)

Combine like terms: 24z + -5z = 19z
-11 + 19z = 2(z + 1)

Reorder the terms:
-11 + 19z = 2(1 + z)
-11 + 19z = (1 * 2 + z * 2)
-11 + 19z = (2 + 2z)

Solving
-11 + 19z = 2 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-11 + 19z + -2z = 2 + 2z + -2z

Combine like terms: 19z + -2z = 17z
-11 + 17z = 2 + 2z + -2z

Combine like terms: 2z + -2z = 0
-11 + 17z = 2 + 0
-11 + 17z = 2

Add '11' to each side of the equation.
-11 + 11 + 17z = 2 + 11

Combine like terms: -11 + 11 = 0
0 + 17z = 2 + 11
17z = 2 + 11

Combine like terms: 2 + 11 = 13
17z = 13

Divide each side by '17'.
z = 0.7647058824

Simplifying
z = 0.7647058824