6(4z-6)=7-5z

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Solution for 6(4z-6)=7-5z equation: 



6(4z-6)=7-5z

We move all terms to the left:

6(4z-6)-(7-5z)=0

We add all the numbers together, and all the variables

6(4z-6)-(-5z+7)=0

We multiply parentheses

24z-(-5z+7)-36=0

We get rid of parentheses

24z+5z-7-36=0

We add all the numbers together, and all the variables

29z-43=0

We move all terms containing z to the left, all other terms to the right

29z=43

z=43/29

z=1+14/29

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