6(5+1c)=5(1c-4)

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Solution for 6(5+1c)=5(1c-4) equation: 



6(5+1c)=5(1c-4)

We move all terms to the left:

6(5+1c)-(5(1c-4))=0

We add all the numbers together, and all the variables

6(c+5)-(5(c-4))=0

We multiply parentheses

6c-(5(c-4))+30=0



We calculate terms in parentheses: -(5(c-4)), so:

5(c-4)

We multiply parentheses

5c-20

Back to the equation:

-(5c-20)



We get rid of parentheses

6c-5c+20+30=0

We add all the numbers together, and all the variables

c+50=0

We move all terms containing c to the left, all other terms to the right

c=-50

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