6(5+2x)=4(2x-1)+4(x+5)

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Solution for 6(5+2x)=4(2x-1)+4(x+5) equation: 


Simplifying
6(5 + 2x) = 4(2x + -1) + 4(x + 5)
(5 * 6 + 2x * 6) = 4(2x + -1) + 4(x + 5)
(30 + 12x) = 4(2x + -1) + 4(x + 5)

Reorder the terms:
30 + 12x = 4(-1 + 2x) + 4(x + 5)
30 + 12x = (-1 * 4 + 2x * 4) + 4(x + 5)
30 + 12x = (-4 + 8x) + 4(x + 5)

Reorder the terms:
30 + 12x = -4 + 8x + 4(5 + x)
30 + 12x = -4 + 8x + (5 * 4 + x * 4)
30 + 12x = -4 + 8x + (20 + 4x)

Reorder the terms:
30 + 12x = -4 + 20 + 8x + 4x

Combine like terms: -4 + 20 = 16
30 + 12x = 16 + 8x + 4x

Combine like terms: 8x + 4x = 12x
30 + 12x = 16 + 12x

Add '-12x' to each side of the equation.
30 + 12x + -12x = 16 + 12x + -12x

Combine like terms: 12x + -12x = 0
30 + 0 = 16 + 12x + -12x
30 = 16 + 12x + -12x

Combine like terms: 12x + -12x = 0
30 = 16 + 0
30 = 16

Solving
30 = 16

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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