6(5+3r)-7r=6(7+2r)

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Solution for 6(5+3r)-7r=6(7+2r) equation: 



6(5+3r)-7r=6(7+2r)

We move all terms to the left:

6(5+3r)-7r-(6(7+2r))=0

We add all the numbers together, and all the variables

6(3r+5)-7r-(6(2r+7))=0

We add all the numbers together, and all the variables

-7r+6(3r+5)-(6(2r+7))=0

We multiply parentheses

-7r+18r-(6(2r+7))+30=0



We calculate terms in parentheses: -(6(2r+7)), so:

6(2r+7)

We multiply parentheses

12r+42

Back to the equation:

-(12r+42)



We add all the numbers together, and all the variables

11r-(12r+42)+30=0

We get rid of parentheses

11r-12r-42+30=0

We add all the numbers together, and all the variables

-1r-12=0

We move all terms containing r to the left, all other terms to the right

-r=12

r=12/-1

r=-12

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