6(5+4)=-4(3i-2)

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Solution for 6(5+4)=-4(3i-2) equation: 



6(5+4)=-4(3i-2)

We move all terms to the left:

6(5+4)-(-4(3i-2))=0

We add all the numbers together, and all the variables

-(-4(3i-2))+69=0



We calculate terms in parentheses: -(-4(3i-2)), so:

-4(3i-2)

We multiply parentheses

-12i+8

Back to the equation:

-(-12i+8)



We get rid of parentheses

12i-8+69=0

We add all the numbers together, and all the variables

12i+61=0

We move all terms containing i to the left, all other terms to the right

12i=-61

i=-61/12

i=-5+1/12

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