6(5+m)=2(4-m)

Solution for 6(5+m)=2(4-m) equation:

6(5+m)=2(4-m)

We move all terms to the left:

6(5+m)-(2(4-m))=0

We add all the numbers together, and all the variables

6(m+5)-(2(-1m+4))=0

We multiply parentheses

6m-(2(-1m+4))+30=0


We calculate terms in parentheses: -(2(-1m+4)), so:

2(-1m+4)

We multiply parentheses

-2m+8

Back to the equation:

-(-2m+8)


We get rid of parentheses

6m+2m-8+30=0

We add all the numbers together, and all the variables

8m+22=0

We move all terms containing m to the left, all other terms to the right

8m=-22

m=-22/8

m=-2+3/4