6(5-2v)=(3v+1)

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Solution for 6(5-2v)=(3v+1) equation: 



6(5-2v)=(3v+1)

We move all terms to the left:

6(5-2v)-((3v+1))=0

We add all the numbers together, and all the variables

6(-2v+5)-((3v+1))=0

We multiply parentheses

-12v-((3v+1))+30=0



We calculate terms in parentheses: -((3v+1)), so:

(3v+1)

We get rid of parentheses

3v+1

Back to the equation:

-(3v+1)



We get rid of parentheses

-12v-3v-1+30=0

We add all the numbers together, and all the variables

-15v+29=0

We move all terms containing v to the left, all other terms to the right

-15v=-29

v=-29/-15

v=1+14/15

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