6(5-2v)=4(v+1)

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Solution for 6(5-2v)=4(v+1) equation: 



6(5-2v)=4(v+1)

We move all terms to the left:

6(5-2v)-(4(v+1))=0

We add all the numbers together, and all the variables

6(-2v+5)-(4(v+1))=0

We multiply parentheses

-12v-(4(v+1))+30=0



We calculate terms in parentheses: -(4(v+1)), so:

4(v+1)

We multiply parentheses

4v+4

Back to the equation:

-(4v+4)



We get rid of parentheses

-12v-4v-4+30=0

We add all the numbers together, and all the variables

-16v+26=0

We move all terms containing v to the left, all other terms to the right

-16v=-26

v=-26/-16

v=1+5/8

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