6(5-y)+3y=27

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Solution for 6(5-y)+3y=27 equation: 



6(5-y)+3y=27

We move all terms to the left:

6(5-y)+3y-(27)=0

We add all the numbers together, and all the variables

6(-1y+5)+3y-27=0

We add all the numbers together, and all the variables

3y+6(-1y+5)-27=0

We multiply parentheses

3y-6y+30-27=0

We add all the numbers together, and all the variables

-3y+3=0

We move all terms containing y to the left, all other terms to the right

-3y=-3

y=-3/-3

y=1

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