6(5c-1)-12=28c+6

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Solution for 6(5c-1)-12=28c+6 equation: 



6(5c-1)-12=28c+6

We move all terms to the left:

6(5c-1)-12-(28c+6)=0

We multiply parentheses

30c-(28c+6)-6-12=0

We get rid of parentheses

30c-28c-6-6-12=0

We add all the numbers together, and all the variables

2c-24=0

We move all terms containing c to the left, all other terms to the right

2c=24

c=24/2

c=12

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