6(5k-8)-20=11(2k-3)=3k

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Solution for 6(5k-8)-20=11(2k-3)=3k equation: 



6(5k-8)-20=11(2k-3)=3k

We move all terms to the left:

6(5k-8)-20-(11(2k-3))=0

We multiply parentheses

30k-(11(2k-3))-48-20=0



We calculate terms in parentheses: -(11(2k-3)), so:

11(2k-3)

We multiply parentheses

22k-33

Back to the equation:

-(22k-33)



We add all the numbers together, and all the variables

30k-(22k-33)-68=0

We get rid of parentheses

30k-22k+33-68=0

We add all the numbers together, and all the variables

8k-35=0

We move all terms containing k to the left, all other terms to the right

8k=35

k=35/8

k=4+3/8

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