6(5r-5)=5(10+2r)

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Solution for 6(5r-5)=5(10+2r) equation: 



6(5r-5)=5(10+2r)

We move all terms to the left:

6(5r-5)-(5(10+2r))=0

We add all the numbers together, and all the variables

6(5r-5)-(5(2r+10))=0

We multiply parentheses

30r-(5(2r+10))-30=0



We calculate terms in parentheses: -(5(2r+10)), so:

5(2r+10)

We multiply parentheses

10r+50

Back to the equation:

-(10r+50)



We get rid of parentheses

30r-10r-50-30=0

We add all the numbers together, and all the variables

20r-80=0

We move all terms containing r to the left, all other terms to the right

20r=80

r=80/20

r=4

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