6(5x+3)+1=3(4x+1)+20

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Solution for 6(5x+3)+1=3(4x+1)+20 equation: 



6(5x+3)+1=3(4x+1)+20

We move all terms to the left:

6(5x+3)+1-(3(4x+1)+20)=0

We multiply parentheses

30x-(3(4x+1)+20)+18+1=0



We calculate terms in parentheses: -(3(4x+1)+20), so:

3(4x+1)+20

We multiply parentheses

12x+3+20

We add all the numbers together, and all the variables

12x+23

Back to the equation:

-(12x+23)



We add all the numbers together, and all the variables

30x-(12x+23)+19=0

We get rid of parentheses

30x-12x-23+19=0

We add all the numbers together, and all the variables

18x-4=0

We move all terms containing x to the left, all other terms to the right

18x=4

x=4/18

x=2/9

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