6(5x+3)+2(3x+2)+6=36x+28

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Solution for 6(5x+3)+2(3x+2)+6=36x+28 equation: 



6(5x+3)+2(3x+2)+6=36x+28

We move all terms to the left:

6(5x+3)+2(3x+2)+6-(36x+28)=0

We multiply parentheses

30x+6x-(36x+28)+18+4+6=0

We get rid of parentheses

30x+6x-36x-28+18+4+6=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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