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6(5x-2)-5(4x-6)=3(3x+5)-10
We move all terms to the left:
6(5x-2)-5(4x-6)-(3(3x+5)-10)=0
We multiply parentheses
30x-20x-(3(3x+5)-10)-12+30=0
We calculate terms in parentheses: -(3(3x+5)-10), so:We add all the numbers together, and all the variables
3(3x+5)-10
We multiply parentheses
9x+15-10
We add all the numbers together, and all the variables
9x+5
Back to the equation:
-(9x+5)
10x-(9x+5)+18=0
We get rid of parentheses
10x-9x-5+18=0
We add all the numbers together, and all the variables
x+13=0
We move all terms containing x to the left, all other terms to the right
x=-13
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