6(5y+7)=7(4y-11)

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Solution for 6(5y+7)=7(4y-11) equation: 



6(5y+7)=7(4y-11)

We move all terms to the left:

6(5y+7)-(7(4y-11))=0

We multiply parentheses

30y-(7(4y-11))+42=0



We calculate terms in parentheses: -(7(4y-11)), so:

7(4y-11)

We multiply parentheses

28y-77

Back to the equation:

-(28y-77)



We get rid of parentheses

30y-28y+77+42=0

We add all the numbers together, and all the variables

2y+119=0

We move all terms containing y to the left, all other terms to the right

2y=-119

y=-119/2

y=-59+1/2

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