6(5y-3)+4(2+y)=228

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Solution for 6(5y-3)+4(2+y)=228 equation: 



6(5y-3)+4(2+y)=228

We move all terms to the left:

6(5y-3)+4(2+y)-(228)=0

We add all the numbers together, and all the variables

6(5y-3)+4(y+2)-228=0

We multiply parentheses

30y+4y-18+8-228=0

We add all the numbers together, and all the variables

34y-238=0

We move all terms containing y to the left, all other terms to the right

34y=238

y=238/34

y=7

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