6(5y-3)+5=4(2y+4)-7

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Solution for 6(5y-3)+5=4(2y+4)-7 equation: 



6(5y-3)+5=4(2y+4)-7

We move all terms to the left:

6(5y-3)+5-(4(2y+4)-7)=0

We multiply parentheses

30y-(4(2y+4)-7)-18+5=0



We calculate terms in parentheses: -(4(2y+4)-7), so:

4(2y+4)-7

We multiply parentheses

8y+16-7

We add all the numbers together, and all the variables

8y+9

Back to the equation:

-(8y+9)



We add all the numbers together, and all the variables

30y-(8y+9)-13=0

We get rid of parentheses

30y-8y-9-13=0

We add all the numbers together, and all the variables

22y-22=0

We move all terms containing y to the left, all other terms to the right

22y=22

y=22/22

y=1

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