6(6+2x+4)=5(5+3x-2)

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Solution for 6(6+2x+4)=5(5+3x-2) equation: 



6(6+2x+4)=5(5+3x-2)

We move all terms to the left:

6(6+2x+4)-(5(5+3x-2))=0

We add all the numbers together, and all the variables

6(2x+10)-(5(3x+3))=0

We multiply parentheses

12x-(5(3x+3))+60=0



We calculate terms in parentheses: -(5(3x+3)), so:

5(3x+3)

We multiply parentheses

15x+15

Back to the equation:

-(15x+15)



We get rid of parentheses

12x-15x-15+60=0

We add all the numbers together, and all the variables

-3x+45=0

We move all terms containing x to the left, all other terms to the right

-3x=-45

x=-45/-3

x=+15

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