6(6c-11)=6(9c-14)

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Solution for 6(6c-11)=6(9c-14) equation: 



6(6c-11)=6(9c-14)

We move all terms to the left:

6(6c-11)-(6(9c-14))=0

We multiply parentheses

36c-(6(9c-14))-66=0



We calculate terms in parentheses: -(6(9c-14)), so:

6(9c-14)

We multiply parentheses

54c-84

Back to the equation:

-(54c-84)



We get rid of parentheses

36c-54c+84-66=0

We add all the numbers together, and all the variables

-18c+18=0

We move all terms containing c to the left, all other terms to the right

-18c=-18

c=-18/-18

c=1

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