6(6y+5)+12=1-(5y-5)

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Solution for 6(6y+5)+12=1-(5y-5) equation: 



6(6y+5)+12=1-(5y-5)

We move all terms to the left:

6(6y+5)+12-(1-(5y-5))=0

We multiply parentheses

36y-(1-(5y-5))+30+12=0



We calculate terms in parentheses: -(1-(5y-5)), so:

1-(5y-5)

determiningTheFunctionDomain
-(5y-5)+1

We get rid of parentheses

-5y+5+1

We add all the numbers together, and all the variables

-5y+6

Back to the equation:

-(-5y+6)



We add all the numbers together, and all the variables

36y-(-5y+6)+42=0

We get rid of parentheses

36y+5y-6+42=0

We add all the numbers together, and all the variables

41y+36=0

We move all terms containing y to the left, all other terms to the right

41y=-36

y=-36/41

y=-36/41

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