6(6z+2)=28

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Solution for 6(6z+2)=28 equation: 



6(6z+2)=28

We move all terms to the left:

6(6z+2)-(28)=0

We multiply parentheses

36z+12-28=0

We add all the numbers together, and all the variables

36z-16=0

We move all terms containing z to the left, all other terms to the right

36z=16

z=16/36

z=4/9

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