6(7+2x)=7(x+11)

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Solution for 6(7+2x)=7(x+11) equation: 



6(7+2x)=7(x+11)

We move all terms to the left:

6(7+2x)-(7(x+11))=0

We add all the numbers together, and all the variables

6(2x+7)-(7(x+11))=0

We multiply parentheses

12x-(7(x+11))+42=0



We calculate terms in parentheses: -(7(x+11)), so:

7(x+11)

We multiply parentheses

7x+77

Back to the equation:

-(7x+77)



We get rid of parentheses

12x-7x-77+42=0

We add all the numbers together, and all the variables

5x-35=0

We move all terms containing x to the left, all other terms to the right

5x=35

x=35/5

x=7

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