6(7+3b)=168

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Solution for 6(7+3b)=168 equation: 



6(7+3b)=168

We move all terms to the left:

6(7+3b)-(168)=0

We add all the numbers together, and all the variables

6(3b+7)-168=0

We multiply parentheses

18b+42-168=0

We add all the numbers together, and all the variables

18b-126=0

We move all terms containing b to the left, all other terms to the right

18b=126

b=126/18

b=7

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