6(7+3x)+5(4-x)=36

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Solution for 6(7+3x)+5(4-x)=36 equation: 



6(7+3x)+5(4-x)=36

We move all terms to the left:

6(7+3x)+5(4-x)-(36)=0

We add all the numbers together, and all the variables

6(3x+7)+5(-1x+4)-36=0

We multiply parentheses

18x-5x+42+20-36=0

We add all the numbers together, and all the variables

13x+26=0

We move all terms containing x to the left, all other terms to the right

13x=-26

x=-26/13

x=-2

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