6(7+3y)=8(12y-2)

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Solution for 6(7+3y)=8(12y-2) equation: 



6(7+3y)=8(12y-2)

We move all terms to the left:

6(7+3y)-(8(12y-2))=0

We add all the numbers together, and all the variables

6(3y+7)-(8(12y-2))=0

We multiply parentheses

18y-(8(12y-2))+42=0



We calculate terms in parentheses: -(8(12y-2)), so:

8(12y-2)

We multiply parentheses

96y-16

Back to the equation:

-(96y-16)



We get rid of parentheses

18y-96y+16+42=0

We add all the numbers together, and all the variables

-78y+58=0

We move all terms containing y to the left, all other terms to the right

-78y=-58

y=-58/-78

y=29/39

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