6(7-2)+2=2(3y-5)

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Solution for 6(7-2)+2=2(3y-5) equation: 



6(7-2)+2=2(3y-5)

We move all terms to the left:

6(7-2)+2-(2(3y-5))=0

We add all the numbers together, and all the variables

-(2(3y-5))+2+65=0

We add all the numbers together, and all the variables

-(2(3y-5))+67=0



We calculate terms in parentheses: -(2(3y-5)), so:

2(3y-5)

We multiply parentheses

6y-10

Back to the equation:

-(6y-10)



We get rid of parentheses

-6y+10+67=0

We add all the numbers together, and all the variables

-6y+77=0

We move all terms containing y to the left, all other terms to the right

-6y=-77

y=-77/-6

y=12+5/6

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