6(7-y)/14=8(5-y)/21

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Solution for 6(7-y)/14=8(5-y)/21 equation: 



6(7-y)/14=8(5-y)/21

We move all terms to the left:

6(7-y)/14-(8(5-y)/21)=0

We add all the numbers together, and all the variables

6(-1y+7)/14-(8(-1y+5)/21)=0

We calculate fractions


(-6y)/()+(-(8(-1y+5)*14)/()=0



We calculate terms in parentheses: +(-(8(-1y+5)*14)/(), so:

-(8(-1y+5)*14)/(

We multiply all the terms by the denominator


-(8(-1y+5)*14)



We calculate terms in parentheses: -(8(-1y+5)*14), so:

8(-1y+5)*14

We multiply parentheses

-112y+560

Back to the equation:

-(-112y+560)



We get rid of parentheses

112y-560

Back to the equation:

+(112y-560)



We get rid of parentheses

(-6y)/()+112y-560=0

We multiply all the terms by the denominator


(-6y)+112y*()-560*()=0

We add all the numbers together, and all the variables

(-6y)+112y*()=0

We get rid of parentheses

-6y+112y*()=0

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