6(7c+2)=18

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Solution for 6(7c+2)=18 equation: 



6(7c+2)=18

We move all terms to the left:

6(7c+2)-(18)=0

We multiply parentheses

42c+12-18=0

We add all the numbers together, and all the variables

42c-6=0

We move all terms containing c to the left, all other terms to the right

42c=6

c=6/42

c=1/7

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