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6(7x-5)(4x+3)=0
We multiply parentheses ..
6(+28x^2+21x-20x-15)=0
We multiply parentheses
168x^2+126x-120x-90=0
We add all the numbers together, and all the variables
168x^2+6x-90=0
a = 168; b = 6; c = -90;
Δ = b2-4ac
Δ = 62-4·168·(-90)
Δ = 60516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{60516}=246$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-246}{2*168}=\frac{-252}{336} =-3/4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+246}{2*168}=\frac{240}{336} =5/7 $
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