6(7y-22)=(7y-22)/6

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Solution for 6(7y-22)=(7y-22)/6 equation: 



6(7y-22)=(7y-22)/6

We move all terms to the left:

6(7y-22)-((7y-22)/6)=0

We multiply parentheses

42y-((7y-22)/6)-132=0

We multiply all the terms by the denominator


42y*6)-((7y-22)-132*6)=0

We add all the numbers together, and all the variables

42y*6)-((7y-22)=0

Wy multiply elements

252y^2=0

a = 252; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·252·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{504}=0$

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