6(7z-5)-12z=3z-7(5z-8)

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Solution for 6(7z-5)-12z=3z-7(5z-8) equation: 



6(7z-5)-12z=3z-7(5z-8)

We move all terms to the left:

6(7z-5)-12z-(3z-7(5z-8))=0

We add all the numbers together, and all the variables

-12z+6(7z-5)-(3z-7(5z-8))=0

We multiply parentheses

-12z+42z-(3z-7(5z-8))-30=0



We calculate terms in parentheses: -(3z-7(5z-8)), so:

3z-7(5z-8)

We multiply parentheses

3z-35z+56

We add all the numbers together, and all the variables

-32z+56

Back to the equation:

-(-32z+56)



We add all the numbers together, and all the variables

30z-(-32z+56)-30=0

We get rid of parentheses

30z+32z-56-30=0

We add all the numbers together, and all the variables

62z-86=0

We move all terms containing z to the left, all other terms to the right

62z=86

z=86/62

z=1+12/31

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