6(8+2x)=3+3(1+3x)

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Solution for 6(8+2x)=3+3(1+3x) equation: 



6(8+2x)=3+3(1+3x)

We move all terms to the left:

6(8+2x)-(3+3(1+3x))=0

We add all the numbers together, and all the variables

6(2x+8)-(3+3(3x+1))=0

We multiply parentheses

12x-(3+3(3x+1))+48=0



We calculate terms in parentheses: -(3+3(3x+1)), so:

3+3(3x+1)

determiningTheFunctionDomain
3(3x+1)+3

We multiply parentheses

9x+3+3

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We get rid of parentheses

12x-9x-6+48=0

We add all the numbers together, and all the variables

3x+42=0

We move all terms containing x to the left, all other terms to the right

3x=-42

x=-42/3

x=-14

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