6(8-x)+36=102-4(3x+24)

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Solution for 6(8-x)+36=102-4(3x+24) equation: 



6(8-x)+36=102-4(3x+24)

We move all terms to the left:

6(8-x)+36-(102-4(3x+24))=0

We add all the numbers together, and all the variables

6(-1x+8)-(102-4(3x+24))+36=0

We multiply parentheses

-6x-(102-4(3x+24))+48+36=0



We calculate terms in parentheses: -(102-4(3x+24)), so:

102-4(3x+24)

determiningTheFunctionDomain
-4(3x+24)+102

We multiply parentheses

-12x-96+102

We add all the numbers together, and all the variables

-12x+6

Back to the equation:

-(-12x+6)



We add all the numbers together, and all the variables

-6x-(-12x+6)+84=0

We get rid of parentheses

-6x+12x-6+84=0

We add all the numbers together, and all the variables

6x+78=0

We move all terms containing x to the left, all other terms to the right

6x=-78

x=-78/6

x=-13

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