6(8m+2-3m);m=-1

Solution for 6(8m+2-3m);m=-1 equation:

6(8m+2-3m)m=-1

We move all terms to the left:

6(8m+2-3m)m-(-1)=0

We add all the numbers together, and all the variables

6(5m+2)m-(-1)=0

We add all the numbers together, and all the variables

6(5m+2)m+1=0

We multiply parentheses

30m^2+12m+1=0

a = 30; b = 12; c = +1;
Δ = b2-4ac
Δ = 122-4·30·1
Δ = 24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{24}=\sqrt{4*6}=\sqrt{4}*\sqrt{6}=2\sqrt{6}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-2\sqrt{6}}{2*30}=\frac{-12-2\sqrt{6}}{60}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+2\sqrt{6}}{2*30}=\frac{-12+2\sqrt{6}}{60}
$