6(8v+3)=4(2v-3)+10

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Solution for 6(8v+3)=4(2v-3)+10 equation: 



6(8v+3)=4(2v-3)+10

We move all terms to the left:

6(8v+3)-(4(2v-3)+10)=0

We multiply parentheses

48v-(4(2v-3)+10)+18=0



We calculate terms in parentheses: -(4(2v-3)+10), so:

4(2v-3)+10

We multiply parentheses

8v-12+10

We add all the numbers together, and all the variables

8v-2

Back to the equation:

-(8v-2)



We get rid of parentheses

48v-8v+2+18=0

We add all the numbers together, and all the variables

40v+20=0

We move all terms containing v to the left, all other terms to the right

40v=-20

v=-20/40

v=-1/2

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