6(8x-4)=12(4x-2)

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Solution for 6(8x-4)=12(4x-2) equation: 



6(8x-4)=12(4x-2)

We move all terms to the left:

6(8x-4)-(12(4x-2))=0

We multiply parentheses

48x-(12(4x-2))-24=0



We calculate terms in parentheses: -(12(4x-2)), so:

12(4x-2)

We multiply parentheses

48x-24

Back to the equation:

-(48x-24)



We get rid of parentheses

48x-48x+24-24=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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