6(8x-7)(x+3)=0

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Solution for 6(8x-7)(x+3)=0 equation:



6(8x-7)(x+3)=0
We multiply parentheses ..
6(+8x^2+24x-7x-21)=0
We multiply parentheses
48x^2+144x-42x-126=0
We add all the numbers together, and all the variables
48x^2+102x-126=0
a = 48; b = 102; c = -126;
Δ = b2-4ac
Δ = 1022-4·48·(-126)
Δ = 34596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{34596}=186$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(102)-186}{2*48}=\frac{-288}{96} =-3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(102)+186}{2*48}=\frac{84}{96} =7/8 $

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