6(9+4b)+2b=-128

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Solution for 6(9+4b)+2b=-128 equation:



6(9+4b)+2b=-128
We move all terms to the left:
6(9+4b)+2b-(-128)=0
We add all the numbers together, and all the variables
6(4b+9)+2b-(-128)=0
We add all the numbers together, and all the variables
2b+6(4b+9)+128=0
We multiply parentheses
2b+24b+54+128=0
We add all the numbers together, and all the variables
26b+182=0
We move all terms containing b to the left, all other terms to the right
26b=-182
b=-182/26
b=-7

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