6(97-1)-10(5y)-3y=22-4(2y-12)+8(y-6)

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Solution for 6(97-1)-10(5y)-3y=22-4(2y-12)+8(y-6) equation: 



6(97-1)-10(5y)-3y=22-4(2y-12)+8(y-6)

We move all terms to the left:

6(97-1)-10(5y)-3y-(22-4(2y-12)+8(y-6))=0

We add all the numbers together, and all the variables

-105y-3y-(22-4(2y-12)+8(y-6))+696=0

We add all the numbers together, and all the variables

-108y-(22-4(2y-12)+8(y-6))+696=0



We calculate terms in parentheses: -(22-4(2y-12)+8(y-6)), so:

22-4(2y-12)+8(y-6)

determiningTheFunctionDomain
-4(2y-12)+8(y-6)+22

We multiply parentheses

-8y+8y+48-48+22

We add all the numbers together, and all the variables

22

Back to the equation:

-(22)



We add all the numbers together, and all the variables

-108y+674=0

We move all terms containing y to the left, all other terms to the right

-108y=-674

y=-674/-108

y=6+13/54

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