6(9y-1)-10(5y)-3y=22-4(2y-12)+(8y-6)

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Solution for 6(9y-1)-10(5y)-3y=22-4(2y-12)+(8y-6) equation: 



6(9y-1)-10(5y)-3y=22-4(2y-12)+(8y-6)

We move all terms to the left:

6(9y-1)-10(5y)-3y-(22-4(2y-12)+(8y-6))=0

We add all the numbers together, and all the variables

-108y+6(9y-1)-(22-4(2y-12)+(8y-6))=0

We multiply parentheses

-108y+54y-(22-4(2y-12)+(8y-6))-6=0



We calculate terms in parentheses: -(22-4(2y-12)+(8y-6)), so:

22-4(2y-12)+(8y-6)

determiningTheFunctionDomain
-4(2y-12)+(8y-6)+22

We multiply parentheses

-8y+(8y-6)+48+22

We get rid of parentheses

-8y+8y-6+48+22

We add all the numbers together, and all the variables

64

Back to the equation:

-(64)



We add all the numbers together, and all the variables

-54y-70=0

We move all terms containing y to the left, all other terms to the right

-54y=70

y=70/-54

y=-1+8/27

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