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6(X-4)+5X(2X-5)=90
We move all terms to the left:
6(X-4)+5X(2X-5)-(90)=0
We multiply parentheses
10X^2+6X-25X-24-90=0
We add all the numbers together, and all the variables
10X^2-19X-114=0
a = 10; b = -19; c = -114;
Δ = b2-4ac
Δ = -192-4·10·(-114)
Δ = 4921
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-\sqrt{4921}}{2*10}=\frac{19-\sqrt{4921}}{20} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+\sqrt{4921}}{2*10}=\frac{19+\sqrt{4921}}{20} $
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