6(a+1)=4(a+3)

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Solution for 6(a+1)=4(a+3) equation: 



6(a+1)=4(a+3)

We move all terms to the left:

6(a+1)-(4(a+3))=0

We multiply parentheses

6a-(4(a+3))+6=0



We calculate terms in parentheses: -(4(a+3)), so:

4(a+3)

We multiply parentheses

4a+12

Back to the equation:

-(4a+12)



We get rid of parentheses

6a-4a-12+6=0

We add all the numbers together, and all the variables

2a-6=0

We move all terms containing a to the left, all other terms to the right

2a=6

a=6/2

a=3

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