6(a+2)+25=42-a+27

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Solution for 6(a+2)+25=42-a+27 equation: 



6(a+2)+25=42-a+27

We move all terms to the left:

6(a+2)+25-(42-a+27)=0

We add all the numbers together, and all the variables

6(a+2)-(-1a+69)+25=0

We multiply parentheses

6a-(-1a+69)+12+25=0

We get rid of parentheses

6a+1a-69+12+25=0

We add all the numbers together, and all the variables

7a-32=0

We move all terms containing a to the left, all other terms to the right

7a=32

a=32/7

a=4+4/7

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