6(a+3)-10=2-(a-4)

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Solution for 6(a+3)-10=2-(a-4) equation:



6(a+3)-10=2-(a-4)
We move all terms to the left:
6(a+3)-10-(2-(a-4))=0
We multiply parentheses
6a-(2-(a-4))+18-10=0
We calculate terms in parentheses: -(2-(a-4)), so:
2-(a-4)
determiningTheFunctionDomain -(a-4)+2
We get rid of parentheses
-a+4+2
We add all the numbers together, and all the variables
-1a+6
Back to the equation:
-(-1a+6)
We add all the numbers together, and all the variables
6a-(-1a+6)+8=0
We get rid of parentheses
6a+1a-6+8=0
We add all the numbers together, and all the variables
7a+2=0
We move all terms containing a to the left, all other terms to the right
7a=-2
a=-2/7
a=-2/7

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